Question 120050
A certain two-digit number has a value that that is three times the sum of its digits. The units digit is one more than three times the tens digit. Find the number. 
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Let the number be 10t+u where t is the tens digit and u is the units digit.
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EQUATION:
10t+u = 3(t+u)
u = 3t+1
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Rearrange the equations:
7t = 2u 
u = 3t+1
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Substitute to solve for "t":
7t = 2(3t+1)
t = 2
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Substitute to solve for "u":
u = 3*2+1 = 7
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The number is 27
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Cheers,
Stan H.