Question 119950
The area of the walk is the area of walk+pool minus area of pool
{{{A[w] = 96 - (6*10)}}}
{{{A[w] = 36}}}
Call the width of the walk {{{x}}}. Going around the pool and adding
up the areas, I have 
{{{A[w] = x^2 + 6x + x^2 + 10x + x^2 + 6x + x^2 + 10x}}}
{{{36 = 4x^2 + 12x + 20x}}}
{{{36 = 4x^2 + 32x}}}
{{{4x^2 + 32x - 36 = 0}}}
{{{x^2 + 8x - 9 = 0}}}
{{{(x + 9)(x - 1) = 0}}}
Either {{{x = -9}}} or {{{x = 1}}} The negative answer is not possible, so,
The width of the walk is 1 meter answer
check answer:
{{{36 = 4x^2 + 12x + 20x}}}
{{{36 = 4*1^2 + 12*1 + 20*1}}}
{{{36 = 4 + 32}}}
{{{36 = 36}}}
OK