Question 119841

Let {{{w=y^(1/3)}}} so the expression goes from {{{y^(1/3)(y^(2/3) + y^(5/3))}}} to {{{w(w^2 + w^5)}}}




{{{w(w^2 + w^5)}}} Start with the given expression




{{{w^3+w^6}}} Distribute {{{w}}} among the terms in the parenthesis



{{{(y^(1/3))^3+(y^(1/3))^6}}} Replace {{{w}}} with {{{y^(1/3)}}}




{{{y^(3/3)+y^(6/3)}}} Multiply the exponents




{{{y+y^2}}} Reduce




So {{{y^(1/3)(y^(2/3) + y^(5/3))}}} simplifies to {{{y+y^2}}}.