Question 119762
I have found this equation from a graph I created:

 y = 50.88e^-0,01x
I already know that y = 50, so I have to find the x. 
:
50.88e^-0.01x = 50
:
Divide both sides by 50.88
e^-0.01x = {{{50/50.88}}}
:
Using nat logs;
ln(e^-0.01x) = ln({{{50/50.88}}})
:
Write the log equiv of exponents
-.01x*n(e^) = ln({{{50/50.88}}})
:
Find the ln of both sides (we know ln of e = 1), so we have:
-.01x = -.0174469
:
x = {{{(-.0174469)/(-.01)}}}
:
x = +1.74469
:
:
Check solution on a good calc: enter 50.88(e^(-.01*1.74469)) = 50
:
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