Question 119770
You must form your two variables and two equations.

First we know that the total amount is 5000.

Let the 8% portion of the money invested = x
Let the 17% portion of the money invested = y.

The first equation would be x + y = 5000, because each portion added together will be 5000.

The second equation is derived by the percentages of each portion that will equal the interest acquired which is 490.  So the second equation would be:

.08x + .17y = 490

Now we have two equations:

x + y = 5000 and .08x + .17y = 490

Solve by substitution.

x + y = 5000

subtract y from both sides

x = 5000 - y

Now substitute 5000 - y for x in the second equation

.08x + .17y = 490

.08(5000 - y) +.17y = 490

Use distributive property

400 - .08y + .17y = 490

Subtract 400 from both sides and simplify

.09y = 90

divide both sides by .09

y = 1000

now substitute the solution for y into the first equation

x = 5000 - y

x = 5000 - 1000

x = 4000

so your answer will be $4000 was invested at 8% and $1000 was invested at 17%.