Question 119666
{{{3(y+2)=(x-4)^2}}}
{{{(y+2)=(1/3)*(x-4)^2}}}
{{{y=-2+(1/3)*(x-4)^2}}}
Since the second term is always positive, y will never be less than -2. 
The range is therefore,
{{{y>=-2}}}
{{{ graph( 300, 300, -10, 10, -10, 10, -2+(1/3)*(x-4)^2) }}}