Question 119713


Looking at {{{4x^2-15x-25}}} we can see that the first term is {{{4x^2}}} and the last term is {{{-25}}} where the coefficients are 4 and -25 respectively.


Now multiply the first coefficient 4 and the last coefficient -25 to get -100. Now what two numbers multiply to -100 and add to the  middle coefficient -15? Let's list all of the factors of -100:




Factors of -100:

1,2,4,5,10,20,25,50


-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations


These factors pair up and multiply to -100

(1)*(-100)

(2)*(-50)

(4)*(-25)

(5)*(-20)

(-1)*(100)

(-2)*(50)

(-4)*(25)

(-5)*(20)


note: remember, the product of a negative and a positive number is a negative number



Now which of these pairs add to -15? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -15


<table border="1"><th>First Number</th><th>Second Number</th><th>Sum</th><tr><td align="center">1</td><td align="center">-100</td><td>1+(-100)=-99</td></tr><tr><td align="center">2</td><td align="center">-50</td><td>2+(-50)=-48</td></tr><tr><td align="center">4</td><td align="center">-25</td><td>4+(-25)=-21</td></tr><tr><td align="center">5</td><td align="center">-20</td><td>5+(-20)=-15</td></tr><tr><td align="center">-1</td><td align="center">100</td><td>-1+100=99</td></tr><tr><td align="center">-2</td><td align="center">50</td><td>-2+50=48</td></tr><tr><td align="center">-4</td><td align="center">25</td><td>-4+25=21</td></tr><tr><td align="center">-5</td><td align="center">20</td><td>-5+20=15</td></tr></table>



From this list we can see that 5 and -20 add up to -15 and multiply to -100



Now looking at the expression {{{4x^2-15x-25}}}, replace {{{-15x}}} with {{{5x+-20x}}} (notice {{{5x+-20x}}} adds up to {{{-15x}}}. So it is equivalent to {{{-15x}}})


{{{4x^2+highlight(5x+-20x)+-25}}}



Now let's factor {{{4x^2+5x-20x-25}}} by grouping:



{{{(4x^2+5x)+(-20x-25)}}} Group like terms



{{{x(4x+5)-5(4x+5)}}} Factor out the GCF of {{{x}}} out of the first group. Factor out the GCF of {{{-5}}} out of the second group



{{{(x-5)(4x+5)}}} Since we have a common term of {{{4x+5}}}, we can combine like terms


So {{{4x^2+5x-20x-25}}} factors to {{{(x-5)(4x+5)}}}



So this also means that {{{4x^2-15x-25}}} factors to {{{(x-5)(4x+5)}}} (since {{{4x^2-15x-25}}} is equivalent to {{{4x^2+5x-20x-25}}})





So {{{4x^2-15x-25}}} factors to {{{(x-5)(4x+5)}}}