Question 119649
{{{(x-3)/((4x-5)(x+1))}}}
the values of x that must be excluded are any values which make the denominator equal to zero. Since the denominator is a product of two terms, the values which make each term equal to zero need to be excluded. Take the first term and equate it to zero:
{{{(4x-5)=0}}}
Solve for x:
{{{4x=5}}}
{{{highlight(x=5/4)}}}
Now, take the second term and equate it to zero:
{{{x+1=0}}}
Solve for x:
{{{highlight(x=-1)}}}
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Good Luck,
tutor_paul@yahoo.com