Question 119516
{{{g(x)=1/(2x-1)}}}
To find an inverse function, switch y and x in the expression and solve for y.
{{{y=1/(2x-1)}}}
{{{highlight(x)=1/(2highlight(y)-1)}}}
{{{x(2y-1)=1}}}
{{{2y-1=1/x}}}
{{{2y=1/x+1}}}
{{{2y=1/x+x/x}}}
{{{2y=(1+x)/x}}}
{{{y=(1+x)/2x}}}
Yes, it is a function. There is only one y value for each x value.