Question 119404
Two consecutive even numbers are such that their sum is greater than 98 decreased by twice the larger. Find the smallest possible values for the integers.
<pre><font size = 4><b>
x = smaller
x+2 = larger

their sum<font color = "red">, x+(x+2),</font> is greater than<font color = "red">, >, 98</font> decreased by<font color = "red">, -,</font> twice the
larger<font color = "red">, 2(x+2)</font>.

So:
<font color = "red">
x+(x+2) > 98-2(x+2)
  x+x+2 > 98-2x-4
   2x+2 > 94-2x
  2x+2x > 94-2
     4x > 92
      x > 23
</font>
Since x is the smaller, it must be greater than 23,
and the larger, x+2, must be 25 or larger.

The smallest two such consecutive even integers are 24 and 26.

Edwin</pre>