Question 119410
May rides her bike the same distance that leah walks. May rides her bike 10 km/h faster than leah walks. If it takes May 1 hour and Leah 3 hours to travel that distance, how fast does each travel? 
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May DATA:
Time = 1 hr ; rate = x km/hr ; distance = 1x = x km
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Leah DATA:
Time = 3 hrs; rate = (x-10)km/hr ; distance = 3(x-10) = 3x-30 km
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EQUATION:
distance = distance
x = 3x-30
2x = 30
 x = 15 km/hr (May's rate)
x-10 = 5 km/hr (Leah's rate)
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Cheers,
Stan H.