Question 119223
How do you solve 1 over p to the 4th power?
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You can't, to solve something it has have an equal sign, (equal to something)
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For example if you had:
{{{(1/p)^4}}} = 4096
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Find the 4th root of both sides
{{{((1/p)^4)^(1/4)}}} = {{{4096^(1/4)}}}
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{{{1/p}}} = 8: (You can see that 8^4 = 4096)
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Multiply both sides by p
:
8p = 1
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p = {{{1/8}}}
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p = .125
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If you substitute .125 for p in the original equation, you can see you will have
{{{1/.125}}} = 8
therefore
8^4 = 4096; which we know is true
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Did this enlighten you somewhat?