<PRE><B>Question 119288</B>
 Traveled for 2 hours at a constant speed. he reduced his speed by 7 km per hour for the next 2 hours. if he traveled 206 km, what was his speed on the first part of the trip.
:
Let s = speed for the 1st part of the trip
Then
(s-7) = speed for the 2nd part of the trip
:
Write a distance equation: Dist = time * speed
:
Fast dist + slow dist = 206 km
2s + 2(s-7) = 206
:
2s + 2s - 14 = 206
:
4s = 206 + 14
:
4s = 220
:
s = {{{220/4}}}
s = 55 km/hr, speed on the 1st part of the trip
:
:
Check solution of s = 55
2(55) + 2(48) = 
110 + 96 = 206; confirms our answer</PRE>