Question 119314
{{{5/(y+1)=4/(y+2)}}}
{{{5(y+2)=4(y+1)}}} Multiply both side by (y+1)(y+2) to get rid of denominators.
{{{5y+10=4y+4}}}
{{{y=-6}}}
Check the answer.
{{{5/(y+1)=4/(y+2)}}}
{{{5/(-6+1)=4/(-6+2)}}}
{{{5/(-5)=4/(-4)}}}
{{{-1=-1}}}
The answer leads to a true statement. 
It's a good answer.