Question 119248


{{{y^2-16=0}}} Start with the given equation


{{{(y+4)(y-4)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{y+4=0}}} or  {{{y-4=0}}} 


{{{y=-4}}} or  {{{y=4}}}    Now solve for y in each case



So our answer is 

 {{{y=-4}}} or  {{{y=4}}}