Question 119095
{{{V=12(1.25)^t}}}
a.) Yes, at time t=0 years, V=12 because (1.25)^t=(1.25)^0=1
b.) You can look at successive years to find the rate.
At year 1, V=12(1.25)=15
Using time t=0 and time t=1, the rate of appreciation equals
(new value minus old value) divided by old value
{{{R=(V[1]-V[0])/V[0]=(15-12)/12=0.25}}}
As a percentage, 0.25 equals 25%
c.)V[5]=12(1.25)^5=12(3.052)=$36.62.
d.)

{{{drawing( 300, 300, -1, 9, -10, 90,grid( 1 ),green(line(0,71.53,8,71.53)),green(line(8,71.53,8,0)),circle(8,71.53,.2),graph( 300, 300, -1, 9, -10, 90, 12(1.25)^x))}}}
Looks like about 8 years.
V[8]=12(1.25)^8=$71.53.