Question 119122
THE TARP HAS THE FOLLOWING DIMENTIOS:
(16+2X)(40+2X)=1100 WHERE X=THE WIDTH OF THE STRIP.
640+80x+32x+4x^2=1100
4x^2+112x+640-1100=0
4x^2+112x-460=0
4(x^2+28x-115)=0
using the quadratic equation {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get
x=(-28+-sqrt[28^2-4*1*-115])/2*1
x=(-28+-sqrt[784+460])/2
x=(-28+-sqrt1244)/2
x=(-28+-35.27)/2
x=(-28+35.27)/2
x=7.27/2
x=3.64 answer for the width of the strip.