Question 119126
{{{2x^2+2x=4}}} Start with the given equation



{{{2x^2+2x-4=0}}}  Subtract 4 from both sides.



{{{2(x+2)(x-1)=0}}} Factor the left side 



Now set each factor equal to zero:

{{{x+2=0}}} or  {{{x-1=0}}} 


{{{x=-2}}} or  {{{x=1}}}    Now solve for x in each case



So our answer is 

 {{{x=-2}}} or  {{{x=1}}} 



Notice if we graph {{{y=2x^2+2x-4}}} we can see that the roots are {{{x=-2}}} and  {{{x=1}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, 2x^2+2x-4) }}}