Question 119097
{{{3kx^2 + 2(x-1) + k = 0}}}
{{{3kx^2 + 2x - 2 + k = 0}}}
The equation can also be expressed as
{{{(x - r[1])(x - r[2]) = 0}}} 
{{{x^2 - (r[1] + r[2])x + r[1]r[2] = 0}}}
If i divide both sides of the given equation by {{{3k}}}, I get
{{{x^2 + 2x / 3k + (k - 2) / 3k = 0}}}
matching up the terms, I get
{{{(k - 2)/3k = r[1]r[2]}}}
The problem says the product of the roots = 1, so
{{{(k - 2)/3k = 1}}}
solve for {{{k}}}
{{{k - 2 = 3k}}}
{{{2k = -2}}}
{{{k = -1}}}