Question 119108
y=-x^2+2x-3
Use the formula for the x-value of the vertex: {{{(-b/2a)}}}
{{{(-2/(2*-1))}}}
x=1
.
Plug (x=1) back into the original equation and solve for the y-value:
y=-x^2+2x-3
y=-(1)^2+2(1)-3
y=-2
Vertex=(1, -2)