Question 119081
{{{4x^2 = 9}}}
{{{sqrt(4x^2)=0+- sqrt(9)}}}
{{{2x=0+- 3}}}

{{{2x=0+3}}} or {{{2x=0-3}}}
{{{2x=3}}} or {{{2x=-3}}}
{{{x=3/2}}} or {{{x=-3/2}}}


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