Question 119085
Let's simplify this first

{{{x(3x+2) =  (x+2)^2}}}
{{{3x^2+2x=x^2+4x+4}}}
{{{(3x^2-x^2)+(2x-4x)-4=0}}}
{{{2x^2-2x-4=0}}}
Divide both sides by 2

{{{x^2-x+2=0}}}

We should find factors x+a and x+b such that:

ab=2
a+b=-1


Searching,

{{{x^2-x+2=(x+1)(x-2)=0}}}
{{{(x+1)(x-2)=0}}}
{{{x+1=0}}} or {{{x-2=0}}}
{{{x=-1}}} or {{{x=2}}}


Power up,
HyperBrain!