Question 119034
Perimeter of a square: {{{P=4S}}} where S is the side length



{{{12x^2-8x+4=4S}}} Plug in {{{P=12x^2-8x+4}}}




{{{(12x^2-8x+4)/4=cross(4/4)S}}} Divide both sides by 4 to isolate and solve for S




{{{(12x^2)/4-(8x)/4+(4)/4=S}}} Simplify and break up the fraction




{{{3x^2-2x+1=S}}} Divide



So the length of one side is {{{S=3x^2-2x+1}}}