Question 119027
12x^2+5x-3=0 
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Solved by graphing:
{{{graph(400,300,-10,10,-10,10,12x^2+5x-3)}}}
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Solved by factoring:
12x^2+9x-4x-3=0
3x(4x+3)-(4x+3)=0
(4x+3)(3x-1)=0
4x+3=0 or 3x-1=0
x = -3/4 or x = 1/3
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Solved by the quadratic formula:
x = [-5 +- sqrt(5^2-4*12*-3)]/(2*12)
x = [-5 +- sqrt(169)]/24
x = [-5 +- 13]/24
x = [-5+13]/24 or x = [-5-13]/24
x = 1/3 or x = -3/4
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Cheers,
Stan H.