Question 118946
A quadratic equation is given by y=2x^2 - 6bx+3.What is the value of 'b' if the equation of the axis of symmetry is x=9 ? I think the answer is 6 but I really don't fully understand, can someone please explain this to me ?
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In the general form of a quadratic. y = ax^2+bx+c,
the axis of symmetry is x = -b/2a Where "b" is the coefficient of the 2nd term.
In Your Problem, "b" = -6b
So -(-6b)/(2*2) = 9
3b/2 = 9
b = 6
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Cheers,
Stan H.