Question 118961
here let width be W and length be L
From given details width is 5 inches shorter than length, thus W=L-5

now perimeter of rectangle is 50.
thus 50=2(L+W)

thus P=2(L+L-5)
thus P=2(2L-5)
thus P=4L-10

b)now as p=50, 50=4L-10;
thus 60=4L
thus L=60/4
thus L=15