Question 118938
{{{8x^2=3x}}}

Subtract 3x to both sides.

{{{8x^2-3x=3x-3x}}}
{{{8x^2-3x=0}}}


Factor {{{8x^2-3x}}}


{{{x(8x-3)=0}}}

This means that either of x or 8x-3 equals zero.

So,

x=0

or 8x-3=0

8x-3+3=0+3
8x+0=3
8x=3
x={{{3/8}}}

Thus, x is either {{{0}}} or {{{3/8}}}


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