Question 118831
{{{4x/3 = 3y/4 +1}}}…………..multiply both sides by {{{12}}} or {{{3*4}}}

{{{(4x/3)( 3*4) = (3y/4)( 3*4) +1}}}…………..simplify

{{{(4x/cross(3))( cross(3)*4) = (3y/cross(4))( 3*cross(4)) +1}}}…………..

{{{(4x)( 4) = (3y)( 3) +1}}}………….. 

{{{16x = 9y +1}}}………….. move {{{1}}} to the left

{{{9y = 16x-1}}}………….. 

{{{16x-1 = 9y}}}………….. 

{{{9y = 16x -1}}}………….. divide both sides by {{{9}}}

{{{y = (16/9)x -1/9}}}…………..