<PRE><B>Question 118745</B>


{{{3x^2(2y+5x)}}} Start with the given expression



{{{(3x^2)(2y)+(3x^2)(5x)}}} Distribute {{{3x^2}}} among the terms in the parenthesis



{{{6x^2y+(3x^2)(5x)}}} Multiply {{{3x^2}}} and  {{{2y}}} to get {{{6x^2y}}}

 

{{{6x^2y+15x^3}}} Multiply {{{3x^2}}} and  {{{5x}}} to get {{{15x^3}}}

 


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Answer:

So {{{3x^2(2y+5x)}}} distributes to {{{6x^2y+15x^3}}}


In other words, {{{3x^2(2y+5x)=6x^2y+15x^3}}}

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