Question 118736

{{{3x^2+x-0=0}}} Start with the given equation



{{{3x^2+x=0}}} Remove the zero term on the left




{{{x(3x+1)=0}}} Factor the left side 



Now set each factor equal to zero:

{{{x=0}}} or  {{{3x+1=0}}} 


{{{x=0}}} or  {{{x=-1/3}}}    Now solve for x in each case



So our answer is 

 {{{x=0}}} or  {{{x=-1/3}}} 



Notice if we graph {{{y=3x^2+x-0}}} we can see that the roots are {{{x=0}}} and  {{{x=-1/3}}} . So this visually verifies our answer.



{{{ graph(500,500,-3,3,-3,3,0, 3x^2+x) }}}