Question 118739

{{{-12*x+6*y=12}}} Start with the given equation


Let's find the x-intercept


To find the x-intercept, let y=0 and solve for x:

{{{-12*x+6*(0)=12}}} Plug in {{{y=0}}}


{{{-12*x=12}}} Simplify


{{{x=12/-12}}} Divide both sides by -12



{{{x=-1}}} Reduce




So the x-intercept is *[Tex \Large \left(-1,0\right)] (note: the x-intercept will always have a y-coordinate equal to zero)




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{{{-12*x+6*y=12}}} Start with the given equation


Now let's find the y-intercept


To find the y-intercept, let x=0 and solve for y:

{{{-12*(0)+6*y=12}}} Plug in {{{x=0}}}


{{{-6*y=12}}} Simplify


{{{x=12/6}}} Divide both sides by 6




{{{y=2}}} Reduce




So the y-intercept is *[Tex \Large \left(0,2\right)] (note: the y-intercept will always have a x-coordinate equal to zero)


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So we have these intercepts:

x-intercept: *[Tex \Large \left(-1,0\right)]


y-intercept: *[Tex \Large \left(0,2\right)]