Question 118718
AREA OF POOL=16*16=256 METERS^2
AREA OF THE THE SURROUNDING FLOOR=256 METERS^2
TOTAL AREA 2*256=512 METERS^2
(16+2X)^2=512
256+64X^2+4X^2=512
4X^2+64X+256-512=0
4X^2+64X-256=0
4(X^2+16X-64)=0
USING THE QUADRATIC EQUATION WE GET:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
X=(-16+-SQRT[16^2-4*1*-64])/2*1
X=(-16+-SQRT[256+256])/2
X=(-16+-SQT512)/2
X=(-16+-22.62)/2
X=(-16+22.62)/2
X=6.62/2
X=3.31M ANSWER FOR THE WIDTH OF THE SURROUNDING FLOOR.
PROOF
(16+2*3.31)^2=512
(16+6.62)^2=512
22.62^2=512
512=512