Question 118704

Let x=number of quarters;  value of quarters=0.25x
Then 103-x=number of dimes; value of dimes=0.10(103-x)

Now we are told that the value of the quarters plus the value of the dimes equals $15.25.  So our equation to solve is:

0.25x+0.10(103-x)=$15.25 get rid of parens

0.25x+10.30-0.10x=15.25  subtract 10.30 from both sides
0.25x+10.30-10.30-0.10x=15.25-10.30  collect like terms
0.15x=4.95  divide both sides by 0.15

x=33---------------number of quarters

103-x=103-33=70------------------number of dimes

CK

33*0.25+70*0.10=15.25
8.25+7.00=15.25
15.25=15.25


Hope this helps---ptaylor