Question 118578
{{{2B(3-B)/(B^2-9)}}}.................{{{B^2-9}}} we can write as {{{-9 + B^2}}} and factor out {{{-1}}}


{{{2B(3-B)/(-1(9 - B^2))}}}


{{{2B(3-B)/(-1(-9 - B^2))}}}


{{{2B(3-B)/(-1(3^2-B^2))}}}


{{{2B(3-B)/(-1(3-B))(3+B)}}}


{{{2B(cross(3-B))/(-1*(cross(3-B))(3+B))}}}


{{{2B/(-(B+3))}}}