Question 118688
Find the area of triangle ABC, if angle A= 46 degree, AC= 4.5cm, and AB= 6.8cm.

---------------
Formla: Area = (1/2)ab(sinC)
Your Problem:
Draw the picture and label appropriate sides as a,b,c
Area = (1/2)bc(sinA)
Area = (1/2)4.5*6.8(sin46) = 11.0059 sq. units
=============
Cheers,
Stan H.