Question 16095
8x^2-10x-2=0
Compare with ax^2+bx+c=0
then a=8,b=-10,c=-2
Using quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (10 +- sqrt( (-10)^2-4*8*-2 ))/(2*8) }}}
{{{x = (10 +- sqrt( 100+64 ))/(16) }}}
{{{x = (10 +- sqrt(164))/(16) }}}
{{{x = (10 +- sqrt(4*41))/(16) }}}
{{{x = (10 +- 2*sqrt(41))/(16) }}}
{{{x = (5 +- sqrt(41))/(8) }}}
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Hope this helps,
Prabhat