Question 118582
{{{(x^2 + 6x +5)/9y^2 * 3y/(x+1)}}}


{{{3y(x^2 + 6x +5)/9y^2  (x+1)}}}......simplify


{{{cross(3)cross(y)(x^2 + 6x +5)/cross(3)3y^cross(2)(x+1)}}}


{{{(x^2 + 6x +5)/3y  (x+1)}}}………. replace {{{6x}}} with {{{x+5x}}}


{{{(x^2 + x + 5x +5)/3y  (x+1)}}}………. group the first two terms together and the last two terms together


{{{((x^2 + x) + (5x +5))/3y (x+1)}}}………. factor a {{{1x}}} out of the first group and factor a {{{5}}} out of the second group


{{{(x(x + 1) + 5(x + 1))/3y  (x+1)}}}………. we have a common term {{{x+1}}} and we can combine the two terms


{{{((x + 5) (x + 1))/3y  (x+1)}}}……….simplify


{{{((x + 5) cross((x + 1)))/((3y)cross((x+1)))}}}……….


{{{(x + 5)/3y }}}……….your answer