Question 118648

{{{6x^2 +12x =0}}}......divide both sides by {{{6}}}

{{{6x^2/6 +12x/6 =0/6}}}......

{{{x^2 +2x =0}}}......factor out common {{{x}}}

{{{x(x +2) =0}}}......

recall: the product is equal to {{{0}}} if one or both terms are equal to {{{0}}}

so,

first solution is: {{{x[1]=0}}}

second solution is: {{{x[2]+2=0}}}....=>....{{{x[2]=-2}}}