Question 118614
First convert the standard equation {{{x-2y=-7}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 1, -2, -7, 2, 1]





Now let's find the equation of the line that is parallel to {{{y=(1/2)x+7/2}}} which goes through (-3,-3)


*[invoke equation_parallel_or_perpendicular "parallel", "1/2", "7/2", -3,-3]