Question 118617
Kyle has 50 coins consistin of nickels and dimes. If he has $4.15, how many of each coin does Kyle possess?
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Let # of nickels be "x" ; Value is 5x cents
# of dimes is "50-x" ; Value is 10(50-x) = 500-10x cents
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EQUATION:
value + value = 415 cents
5x + 500-10x = 415
-5x = -85
x = 17 (# of nickels)
50-x = 33 (# of dimes)
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Cheers,
Stan H.