Question 118543
Angle {{{T }}}is {{{40°}}}° greater than angle {{{S}}}

=> {{{T = S + 40}}}
 
Angle {{{R}}} is {{{8}}}{{{ times}}} angle {{{S}}}

=> {{{ R = 8S }}}


 What is the measure of each angle?

The {{{sum}}} of all three angles is {{{180}}}° 

{{{ T + S + R = 180}}}……..substitute {{{T}}} and {{{R}}}

{{{ (S + 40) + S + 8S = 180}}}° ……..

{{{ 10S + 40= 180}}}……..

{{{ 10S = 180- 40}}}……..

{{{ 10S = 140 }}}……..

{{{ S = 140/10 }}}……..

{{{ S = 14}}}° ……..

Now find {{{T}}} and {{{R}}}


{{{T = S + 40}}}

{{{T = 14 + 40}}}
	
{{{T = 54 }}}° 



{{{ R = 8S }}}

{{{ R = 8(14) }}}	

{{{ R = 112}}}° 


Check the sum:

{{{ T + S + R = 180}}}……..

{{{ 54 + 14+ 112= 180}}}……..

{{{ 180 = 180}}}° ……..