Question 118526


{{{(3x+4)(2x+3)}}} Start with the given expression


Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3x)+4)(highlight(2x)+3)}}} Multiply the First terms:{{{(3x)*(2x)=6x^2}}}



{{{(highlight(3x)+4)(2x+highlight(3))}}} Multiply the Outer terms:{{{(3x)*(3)=9x}}}



{{{(3x+highlight(4))(highlight(2x)+3)}}} Multiply the Inner terms:{{{(4)*(2x)=8x}}}



{{{(3x+highlight(4))(2x+highlight(3))}}} Multiply the Last terms:{{{(4)*(3)=12}}}



{{{6x^2+9x+8x+12}}} Now collect every term to make a single expression




{{{6x^2+17x+12}}} Now combine like terms



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Answer:

So {{{(3x+4)(2x+3)}}} foils and simplifies to  {{{6x^2+17x+12}}}


In other words, {{{(3x+4)(2x+3)=6x^2+17x+12}}}