Question 17888
2X^4+11X^3+19X^2+X-29=(X^2+4X+6)*(_____)+(_____)
Using standard long division,
<pre>
x^2+4x+6| 2X^4 + 11x^3 + 19x^2 + x - 29 | 2x^2 + 3x - 5
          2x^4 + 8x^3  + 12x^2
          --------------------
                 3x^3  + 7x^2  + x  - 29
                 3x^3  + 12x^2 +18x
                 ------------------
                        -5x^2  -17x - 29
                        -5x^2  -20x - 30
                        ----------------
                               3x + 1
</pre>
2X^4+11X^3+19X^2+X-29=(X^2+4X+6)*(2x^2+3x-5)+(3x+1)
<P>
{{{ (X^2+4X+6)*(2x^2+3x-5)+(3x+1) }}}
<P>
Hope this helps,
Prabhat