Question 118379
Since {{{g(y)=y/abs(y)}}}, this means {{{g(2)-g(-200)}}} is:


{{{2/abs(2)-(-200)/abs(-200)}}} note: just replace the first pair of "y"s with 2 and the second pair of "y"s with -200



{{{2/2-(-200)/200}}} Evaluate the absolute value of 2 to get 2. Evaluate the absolute value of -200 to get 200. 



{{{1-(-1)}}} Divide {{{2/2}}} to get 1. Divide {{{-200/200}}} to get -1.  



{{{1+1}}} Rewrite {{{1-(-1)}}} as 1+1. 


{{{2}}} Add


So {{{g(2)-g(-200)=2}}}