Question 118161
simplify (2x to the power of -2 times y to the power of 3 over x to the power of 2 times y to the power of -3) to the power of -1 
:
Assume that you mean:
{{{(((2x^-2*y^3))/((x^2*y^-3)))^-1}}}
:
You can get rid of the outside exponent of -1 by inverting the fraction:
{{{((x^2*y^-3))/((2x^-2*y^3))}}}
:
Add the like term exponents so they will be positive:
{{{((x^(2+2)))/((2*y^(3+3)))}}} = {{{((x^4))/((2y^6))}}}
:
Remember when you divide, the exponents are subtracted, but if it's a negative
 exponent, you have a minus a minus, which is a plus
:
Looks like the answer is d, doesn't it