Question 118314
{{{8a^3+27b^3}}} Start with the given expression



{{{(2a)^3+(3b)^3}}} Rewrite {{{8a^3}}} as {{{(2a)^3}}} and {{{27b^3}}} as {{{(3b)^3}}}


{{{(2a+3b)(4a^2-6ab+9b^2)}}} Now factor using the sum of cubes. Remember the sum of cubes formula is {{{x^3+y^3=(x+y)(x^2-xy+y^2)}}}



So {{{8a^3+27b^3}}} factors to {{{(2a+3b)(4a^2-6ab+9b^2)}}}