Question 118268
The sum of two digits is 8. If the digits of the number are reversed, the number formed is 36 more than the number. What is the number?
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Let the number be 10t+u where t is the tens digit and u is the units digit.
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EQUATIONS:
t+u = 8
10u+t = 10t+u +36
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Rearrange:
t+u=8
9u=9t+36
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Simplify
t+u=8
t-u=-4
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Add to solve for "t":
2t = 4
t = 2 (tens digit of the original number)
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Substitute to solve for "U"
2+u = 8
u = 6 (units digit of the original number)
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Original number: 26
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Cheers,
Stan H.