<PRE><B>Question 118267</B>
3x^2 + 4y^2 + 8y=8 
3x^2 + 4(y^2+2y+1) = 8+4
3x^2 + 4(y+1)^2 = 12
3x^2/12 + 4(y+1)^2/12 = 1
x^2/4 + (y+1)^2/3 =1
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Cheers,
Stan H.


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