Question 118230
(4x +12) *  x^2     ÷2
           _____________  
           2x-6    x-3
:
Trying to sort this out, I came up with:
(4x + 12) * {{{x^2/((2x-6))}}} / {{{2/((x-3))}}}
:
Invert the dividing fraction and multiply; 
(4x + 12) * {{{x^2/((2x-6))}}} * {{{((x-3))/2}}}
:
Do some factoring here
4(x + 3) * {{{x^2/(2(x-3))}}} * {{{((x-3))/2}}}
:
Cancel (x-3)
4(x + 3) * {{{x^2/(2)}}} * {{{1/2}}}
:
4(x + 3) * {{{x^2/(4)}}}
:
Cancel 4, leaving us with:
{{{x^2(x+3)}}}
:
If this is not what you meant, well, what can I say?