<PRE><B>Question 118256</B>
write a quadratic function in standard form that goes through the given points (1,3) (2,1) (-2,-15)
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Quadratic Form:
y = ax^2 + bx + c
Substitute each pair of x/y values then solve for a,b,c
a + b +c = 3
4a+2b +c = 1
4a-2b +c = -15
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I used the Matrix function on a TI calculator to get:
a = -2
b = 4
c = 1
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EQUATION:
y = -2x^2+4x+1
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Cheers,
Stan H.</PRE>